słowo zawierające wartości numeryczne

Question

Jak rozpoznać słowo z wyrażeniem regularnym, które może zawierać w nim dane liczbowe. Więc chcę przechwycić "ciąg1", "12 cali", "log4net". Ale nie 12/11/2011 czy 18? Unfortunetly \b[\p{L}\d\p{M}]+\b również pobiera wartości liczbowe.

Answer 1

to:

Regex regexObj = new Regex(@"\b(?=\S*[a-z])\w+\b", RegexOptions.IgnoreCase); 
    Match matchResults = regexObj.Match(subjectString); 
    while (matchResults.Success) { 
     // matched text: matchResults.Value 
     // match start: matchResults.Index 
     // match length: matchResults.Length 
     matchResults = matchResults.NextMatch(); 
    } 

jest w umyśle.

" 
\b   # Assert position at a word boundary 
(?=   # Assert that the regex below can be matched, starting at this position (positive lookahead) 
    \S   # Match a single character that is a “non-whitespace character” 
     *   # Between zero and unlimited times, as many times as possible, giving back as needed (greedy) 
    [a-z]  # Match a single character in the range between “a” and “z” 
) 
\w   # Match a single character that is a “word character” (letters, digits, etc.) 
    +   # Between one and unlimited times, as many times as possible, giving back as needed (greedy) 
\b   # Assert position at a word boundary 
" 

Answer 2

Chcesz dopasować słowo do liter i cyfr? To powinno działać: \b(\w+\d+|\d+\w+)[\w\d]+\b.