Unsupported field: Year when formatting a instant to Date ISO

Question

Próbuję sformatować Instant na datę ldap ISO8601, ale nie powiedzie się na f.format (Instant.now()); :

String input = "20161012235959.0Z"; 
DateTimeFormatter f = DateTimeFormatter.ofPattern ("uuuuMMddHHmmss[,S][.S]X"); 
OffsetDateTime odt = OffsetDateTime.parse (input , f); 
Instant instant = odt.toInstant(); 

f.format(Instant.now()); 

a błąd jest:

java.time.temporal.UnsupportedTemporalTypeException: Unsupported field: Year 

    at java.time.Instant.getLong(Instant.java:603) 
    at java.time.format.DateTimePrintContext.getValue(DateTimePrintContext.java:298) 
    at java.time.format.DateTimeFormatterBuilder$NumberPrinterParser.format(DateTimeFormatterBuilder.java:2540) 
    at java.time.format.DateTimeFormatterBuilder$CompositePrinterParser.format(DateTimeFormatterBuilder.java:2179) 
    at java.time.format.DateTimeFormatter.formatTo(DateTimeFormatter.java:1746) 
    at java.time.format.DateTimeFormatter.format(DateTimeFormatter.java:1720) 
... 
... 

Answer 1

Aby sformatować natychmiastowy wymagany jest czas strefy.

String input = "20161012235959.0Z"; 
DateTimeFormatter f = DateTimeFormatter 
     .ofPattern ("uuuuMMddHHmmss.SX") 
     .withLocale(Locale.FRANCE) 
     .withZone(ZoneId.of("UTC")); 
OffsetDateTime odt = OffsetDateTime.parse (input , f); 
Instant instant = odt.toInstant(); 

System.out.println(input); 
System.out.print(f.format(instant));