5
Próbuję utworzyć kod, który może serializować i deserializować bibliotekę Klasy w rysunku programu AutoCAD. To pytanie ma niewiele wspólnego z programem AutoCAD, ponieważ jest to powód, dla którego nie mogę go debugować w normalny sposób. Zacząłem ten projekt od this article i udało mi się uruchomić jego kod. Jednak sposób w jaki zbudowany jest jego kod, wymagałby ode mnie, aby wszystkie moje klasy dziedziczyły z jego podstawowego obiektu. Ponieważ wyraźnie jest to zapach kodu, wiedziałem, że muszę zamiast tego stworzyć interfejs. Poniżej znajduje się kod, który zakończyłem.Kod Serializacji Powoduje Nieobsługiwany Wyjątek
Pierwsza sekcja to kod odpowiedzialny za wykonanie serializacji w rysunku programu AutoCAD.
Druga sekcja jest przykładem klasy, która implementuje mój własny interfejs serializacji
public class Commands
{
public class MyUtil
{
const int kMaxChunkSize = 127;
public ResultBuffer StreamToResBuf(MemoryStream ms, string appName)
{
ResultBuffer resBuf = new ResultBuffer(new TypedValue((int)DxfCode.ExtendedDataRegAppName, appName));
for (int i = 0; i < ms.Length; i += kMaxChunkSize)
{
int length = (int)Math.Min(ms.Length - i, kMaxChunkSize);
byte[] datachunk = new byte[length];
ms.Read(datachunk, 0, length);
resBuf.Add(new TypedValue((int)DxfCode.ExtendedDataBinaryChunk, datachunk));
}
return resBuf;
}
public MemoryStream ResBufToStream(ResultBuffer resBuf)
{
MemoryStream ms = new MemoryStream();
TypedValue[] values = resBuf.AsArray();
// Start from 1 to skip application name
for (int i = 1; i < values.Length; i++)
{
byte[] datachunk = (byte[])values[i].Value;
ms.Write(datachunk, 0, datachunk.Length);
}
ms.Position = 0;
return ms;
}
public void NewFromEntity(IClearspanSerializable objectToSave, Entity ent)
{
using (ResultBuffer resBuf = ent.GetXDataForApplication("Member"))
{
BinaryFormatter bf = new BinaryFormatter();
bf.Binder = new MyBinder();
MemoryStream ms = this.ResBufToStream(resBuf);
objectToSave.SetObjectData(bf.Deserialize(ms));
}
}
public void SaveToEntity(IClearspanSerializable objectToSave, Entity ent)
{
// Make sure application name is registered
// If we were to save the ResultBuffer to an Xrecord.Data,
// then we would not need to have a registered application name
Transaction tr = ent.Database.TransactionManager.TopTransaction;
RegAppTable regTable = (RegAppTable)tr.GetObject(ent.Database.RegAppTableId, OpenMode.ForWrite);
if (!regTable.Has("Member"))
{
RegAppTableRecord app = new RegAppTableRecord();
app.Name = "Member";
regTable.Add(app);
tr.AddNewlyCreatedDBObject(app, true);
}
BinaryFormatter bf = new BinaryFormatter();
MemoryStream ms = new MemoryStream();
bf.Serialize(ms, objectToSave);
ms.Position = 0;
ent.XData = this.StreamToResBuf(ms, "Member");;
}
}
public sealed class MyBinder : SerializationBinder
{
public override Type BindToType(string assemblyName, string typeName)
{
return Type.GetType(string.Format("{0}, {1}",
typeName, assemblyName));
}
}
[CommandMethod("SaveClassToEntityXData", CommandFlags.Modal)]
public void SaveClassToEntityXData(IClearspanSerializable objectToSerialize)
{
Database db = Application.DocumentManager.MdiActiveDocument.Database;
Editor ed = Application.DocumentManager.MdiActiveDocument.Editor;
PromptEntityResult per = ed.GetEntity("Select entity to save class to:\n");
if (per.Status != PromptStatus.OK)
return;
MyUtil util = new MyUtil();
// Save it to the document
using (Transaction tr = db.TransactionManager.StartTransaction())
{
Entity ent = (Entity)tr.GetObject(per.ObjectId, OpenMode.ForWrite);
util.SaveToEntity(objectToSerialize, ent);
tr.Commit();
}
// Write some info about the results
//ed.WriteMessage("Content of MyClass we serialized:\n {0} \n", mc.ToString());
}
[CommandMethod("GetClassFromEntityXData", CommandFlags.Modal)]
public void GetClassFromEntityXData(IClearspanSerializable objectToRestore)
{
Database db = Application.DocumentManager.MdiActiveDocument.Database;
Editor ed = Application.DocumentManager.MdiActiveDocument.Editor;
MyUtil util = new MyUtil();
PromptEntityResult per = ed.GetEntity("Select entity to get class from:\n");
if (per.Status != PromptStatus.OK)
return;
// Get back the class
using (Transaction tr = db.TransactionManager.StartTransaction())
{
Entity ent = (Entity)tr.GetObject(per.ObjectId, OpenMode.ForRead);
util.NewFromEntity(objectToRestore, ent);
tr.Commit();
}
}
}
Oto obojętne klasy I 'm próby przetestować z:
[Serializable]
public class MattMember: IClearspanSerializable
{
public string Name;
List<int> MattsInts;
public MattMember(string passedName, List<int> passedInts)
{
Name = passedName;
MattsInts = passedInts;
}
[SecurityPermission(SecurityAction.LinkDemand, Flags = SecurityPermissionFlag.SerializationFormatter)]
public void GetObjectData(SerializationInfo info, StreamingContext context)
{
info.AddValue("Name", Name);
info.AddValue("MattsInts", MattsInts);
}
[SecurityPermission(SecurityAction.LinkDemand, Flags = SecurityPermissionFlag.SerializationFormatter)]
public void SetObjectData(SerializationInfo info, StreamingContext context)
{
if (info == null)
{
throw new System.ArgumentNullException("info");
}
Name = (string)info.GetValue("Name", typeof(string));
MattsInts = (List<int>)info.GetValue("MattsInts", typeof(List<int>));
}
void IClearspanSerializable.SetObjectData(object objectInDisguise)
{
if (objectInDisguise == null)
{
throw new System.ArgumentNullException("info");
}
MattMember objectToCopy = (MattMember)objectInDisguise;
Name = objectToCopy.Name;
MattsInts = objectToCopy.MattsInts;
}
}
i tutaj jest interfejs :
public interface IClearspanSerializable
{
void GetObjectData(SerializationInfo info, StreamingContext context);
void SetObjectData(object objectInDisguise);
}
Kiedy próbuję uruchomić kod w programie AutoCAD, wszystko co otrzymuję to błąd lub. Co prowadzi mnie do przekonania, że istnieje prosty błąd w mojej inicjalizacji moich zajęć. Brak moich punktów przerwania zostaje trafiony.
Jak debugować to? i gdzie skręciłem moją inicjalizację?
[EDIT] -Tutaj jest to, co jest w "Szczegóły":
******************************************************************************
Application does not support just-in-time (JIT)
debugging. See the end of this message for details.
************** Exception Text **************
System.ArgumentException: Cannot bind to the target method because its signature or security transparency is not compatible with that of the delegate type.
at System.Delegate.CreateDelegate(Type type, Object firstArgument, MethodInfo method, Boolean throwOnBindFailure)
at System.Delegate.CreateDelegate(Type type, Object firstArgument, MethodInfo method)
at Autodesk.AutoCAD.Runtime.CommandClass.InvokeWorker(MethodInfo mi, Object commandObject, Boolean bLispFunction)
at Autodesk.AutoCAD.Runtime.CommandClass.InvokeWorkerWithExceptionFilter(MethodInfo mi, Object commandObject, Boolean bLispFunction)
at Autodesk.AutoCAD.Runtime.PerDocumentCommandClass.Invoke(MethodInfo mi, Boolean bLispFunction)
at Autodesk.AutoCAD.Runtime.CommandClass.CommandThunk.Invoke()
************** Loaded Assemblies **************
mscorlib
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Acdbmgd
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System
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accoremgd
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System.Core
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AcMrUi.resources
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AcMultiLineUi.resources
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AcRecoverAll.resources
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AcScaleList.resources
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AcUnderlay.resources
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AcViewTransitionsUi.resources
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----------------------------------------
AdskConnectionPointMgd.resources
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AcCalcUi.resources
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----------------------------------------
AcLivePreviewContext
Assembly Version: 0.0.0.0
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CodeBase: file:///C:/Program%20Files/Autodesk/AutoCAD%202015/AcWindows.dll
----------------------------------------
AcDialogToolTips
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AcDialogToolTips.resources
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CodeBase: file:///C:/Program%20Files/Autodesk/AutoCAD%202015/en-US/AcDialogToolTips.resources.DLL
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Write To Block
Assembly Version: 1.0.5276.26438
Win32 Version: 1.0.0.0
CodeBase: file:///C:/Users/Administrator/Documents/Clearspan/AutoCAD%20Projects/Write%20To%20Block/Write%20To%20Block/bin/Debug/Write%20To%20Block.dll
----------------------------------------
************** JIT Debugging **************
Application does not support Windows Forms just-in-time (JIT)
debugging. Contact the application author for more
information.
proszę kliknąć przycisk Szczegóły pierwszy i wkleić szczegółów do postu. Zastanawiam się, dlaczego to pytanie dostaje 5 przegranych ... – Matt
Jaka jest wersja/bitness AutoCAD? –
To jest AutoCAD 2015 na 32-bitowej maszynie z Windows 7 –