Analizy parsowania Scala i HTML

Question

Jak załadować dokument HTML DOM do Scala? Singlet XML miał błędy podczas próby załadowania tagów xmlns.

import java.net._ 
import java.io._ 
import scala.xml._ 

object NetParse { 

    import java.net.{URLConnection, URL} 
    import scala.xml._ 

    def netParse(sUrl: String): Elem = { 
     var url = new URL(sUrl) 
     var connect = url.openConnection 

     XML.load(connect.getInputStream) 
    } 
} 

---

Wreszcie znalazłem rozwiązanie! - Wymaga Scala 2.7.7 lub wyższą do pracy (2.7.0 ma fatalny błąd): How-to-use-TagSoup-with-Scala-XML

Answer 1

To może pomóc Processing real world HTML as if it were XML in scala

Answer 2

Spróbuj użyć scala.xml.parsing.XhtmlParser zamiast.

Answer 3

/* 
Copyright (c) 2008 Florian Hars, BIK Aschpurwis+Behrens GmbH, Hamburg 
Copyright (c) 2002-2008 EPFL, Lausanne, unless otherwise specified. 
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Swiss Federal Institute of Technology (EPFL), Lausanne, Switzerland. 

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    may be used to endorse or promote products derived from this 
    software without specific prior written permission. 


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*/ 

package tagsoup 

import org.xml.sax.InputSource 
import javax.xml.parsers.SAXParser 
import org.ccil.cowan.tagsoup.jaxp.SAXFactoryImpl 
import scala.xml.parsing.FactoryAdapter 
import scala.xml._ 

class TagSoupFactoryAdapter extends FactoryAdapter { 

    val parserFactory = new SAXFactoryImpl 
    parserFactory.setNamespaceAware(false) 

    val emptyElements = Set("area", "base", "br", "col", "hr", "img", 
         "input", "link", "meta", "param") 

    /** Tests if an XML element contains text. 
    * @return true if element named <code>localName</code> contains text. 
    */ 
    def nodeContainsText(localName: String) = !(emptyElements contains localName) 

    /** creates a node. 
    */ 
    def createNode(pre:String, label: String, attrs: MetaData, 
      scpe: NamespaceBinding, children: List[Node]): Elem = { 
    Elem(pre, label, attrs, scpe, children:_*); 
    } 

    /** creates a text node 
    */ 
    def createText(text:String) = 
    Text(text); 

    /** Ignore Processing Instructions 
    */ 
    def createProcInstr(target: String, data: String) = Nil 

    /** load XML document 
    * @param source 
    * @return a new XML document object 
    */ 
    override def loadXML(source: InputSource) = { 
    val parser: SAXParser = parserFactory.newSAXParser() 

    scopeStack.push(TopScope) 
    parser.parse(source, this) 
    scopeStack.pop 
    rootElem 
    } 

} 

How-to-use-TagSoup-with-Scala-XML

Answer 4

Właśnie próbował wykorzystać tę odpowiedź z Scala 2.8.1 i skończyło się za pomocą pracy z:

http://www.hars.de/2009/01/html-as-xml-in-scala.html

Interesującą nieco, że potrzebne było:

val parserFactory = new org.ccil.cowan.tagsoup.jaxp.SAXFactoryImpl 
val parser = parserFactory.newSAXParser() 
val source = new org.xml.sax.InputSource("http://www.scala-lang.org") 
val adapter = new scala.xml.parsing.NoBindingFactoryAdapter 
adapter.loadXML(source, parser) 

Answer 5

Scala Skrobak

Polecam Scala Scraper który pozwala analizować HTML elegancko tak:

// Parse elements from files, URLs or plain strings 
val browser = JsoupBrowser() 
val doc = browser.parseFile("core/src/test/resources/example.html") 
val doc2 = browser.get("http://example.com") 
val doc3 = browser.parseString("<html><h1>parse me</h1></html>") 

// Extract the text inside the element with id "header" 
doc >> text("#header") 

// Extract the <span> elements inside #menu 
val items = doc >> elementList("#menu span") 

// From each item, extract all the text inside their <a> elements 
items.map(_ >> allText("a")) 

Przykłady zostały zaczerpnięte z Scala Scraper na readme.