'Większy lub równy' i 'mniejszy lub równy' CODEIGNITER

Question

Muszę zapytać o coś, co ma warunek, gdzie "> =" i "= <", ale nie mam szczęścia. To jest w CODEIGNITER.

Jest to naturalny sposób w zapytaniu mysql:

SELECT COUNT(payment.keyid) AS rec_count, `product_key`.`client_name`, 
`product_key`.`contact_email`, `product_key`.`status`, `product_key`.`id`, 
`payment`.`paymentdate`, (payment.id) as pid, `payment`.`subscription_type` 
FROM (`product_key`) 
LEFT OUTER JOIN `payment` ON `payment`.`keyid`=`product_key`.`id` 
WHERE `payment`.`paymentdate` >= '2013-08-01' 
    AND `payment`.`paymentdate` =< '2013-08-31' 
    AND `status` = 'purchased' 
GROUP BY `product_key`.`id` 
ORDER BY `client_name` asc 

I to jest to, co mam:

return $this->db 
    ->select('COUNT(payment.keyid) AS rec_count') 
    ->select('product_key.client_name, product_key.contact_email, product_key.status, product_key.id, payment.paymentdate, (payment.id) as pid,payment.subscription_type') 
    ->from('product_key')   
    ->where('payment.paymentdate >=', $month_start) 
    ->where('payment.paymentdate =<', $month_end) 
    ->where('status', 'purchased') 
    ->join('payment', 'payment.keyid=product_key.id', 'left outer') 
    ->order_by('client_name', "asc") 
    ->group_by('product_key.id') 
    ->get() 
    ->result(); 

Może ktoś może mi pomóc w tej sprawie. Dzięki.

Answer 1

Zmień =< na <=.

Również przetestowałem twoje bieżące zapytanie w phpmyadmin, ponieważ nie mogłem uwierzyć, że to nie wyrzuca błędu. Ale moje to robi. Tak więc twoje zapytanie nie powinno działać w phpmyadmin.

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '=< ...' at line ... 

Answer 2

Spróbuj:

$this->db 
->select('COUNT(payment.keyid) AS rec_count, product_key.client_name, product_key.contact_email, product_key.status, product_key.id, payment.paymentdate, (payment.id) as pid, payment.subscription_type', false) 
->from('product_key') 
->join('payment', 'payment.keyid=product_key.id', 'LEFT OUTER') 
->where('payment.paymentdate >=', '2013-08-01') 
->where('payment.paymentdate =<', '2013-08-31') 
->where('status', 'purchased') 
->group_by('product_key.id') 
->order_by('client_name', 'asc') 
->get(); 

Answer 3

Spróbuj zmienić =< do <= jak

->where('payment.paymentdate >=', $month_start) 
->where('payment.paymentdate <=', $month_end) 

I lepszego ale nie cumpolsury dołączyć tabelę przed gdzie condition.Now zapytaniu powinien być podobny do

->select('COUNT(payment.keyid) AS rec_count') 
->select('product_key.client_name, product_key.contact_email, product_key.status, product_key.id, payment.paymentdate, (payment.id) as pid,payment.subscription_type') 
->from('product_key')   
->join('payment', 'payment.keyid=product_key.id', 'left outer')  
->where('payment.paymentdate >=', $month_start) 
->where('payment.paymentdate <=', $month_end) 
->where('status', 'purchased') 
->order_by('client_name', "asc") 
->group_by('product_key.id') 
->get() 

Answer 4

z tego co wiem, można napisać je jak tego

$this->db->select('COUNT(payment.keyid) AS rec_count, product_key.client_name, product_key.contact_email, product_key.status, product_key.id, payment.paymentdate, (payment.id) as pid, payment.subscription_type', false); 
$this->db->where('payment.paymentdate >= "2013-08-01"'); 
$this->db->where('payment.paymentdate <= "2013-08-31"'); 
$this->db->where('status', 'purchased'); 
$this->db->group_by('product_key.id'); 
$this->db->order_by('client_name', 'asc'); 
$this->db->join('payment', 'payment.keyid=product_key.id', 'LEFT OUTER') 
$this->db->get('product_key');