2012-11-04 7 views
5

Mam następujące zapytanie:Aktualizuj wiele wierszy w tabeli na podstawie wyniku z podzapytanie

SELECT 
    stat.mcq_id, 
    ROUND(stat.total_score/stat.num_taken, 2) AS avg_score 
    FROM (
     SELECT 
     user_mcq.mcq_id, 
     SUM(score) AS total_score, 
     COUNT(user_mcq.id) AS num_taken 
     FROM user_mcq 
     INNER JOIN user ON (user.id = user_mcq.user_id) 
     WHERE user.level_id =3 
     AND user_mcq.is_complete =1 
     GROUP BY user_mcq.mcq_id 
    ) AS stat 

ta produkuje:

mcq_id avg_score 
1  5.75 
2  9.22 
6  8.81 
7  8.94 
14  7.00 
16  9.46 

Chciałbym użyć tego zaktualizować innej tabeli o nazwie mcq korzystania mcq_id z wyniku, który można porównać z mcq.id

Próbowałem następujące, ale bez powodzenia:

UPDATE mcq SET mcq.avg_score = stats.avg_score FROM (
    SELECT 
    stat.mcq_id, 
    ROUND(stat.total_score/stat.num_taken, 2) AS avg_score 
    FROM (
     SELECT 
     user_mcq.mcq_id, 
     SUM(score) AS total_score, 
     COUNT(user_mcq.id) AS num_taken 
     FROM user_mcq 
     INNER JOIN user ON (user.id = user_mcq.user_id) 
     WHERE user.level_id =3 
     AND user_mcq.is_complete =1 
     GROUP BY user_mcq.mcq_id 
    ) AS stat 
) AS stats 
WHERE mcq.id = stats.mcq_id; 

Daje:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM (SELECT stat.mcq_id, ROUND(stat.total_score/stat.num_taken, 2) A' at line 1 

Odpowiedz

12

myślę, że można użyć sprzężenia ze zdolnego tabeli i zaktualizować kolumny jak poniżej:

UPDATE mcq, 
     (SELECT 
      stat.mcq_id, 
      ROUND(stat.total_score/stat.num_taken, 2) AS avg_score 
      FROM (SELECT 
        user_mcq.mcq_id, 
        SUM(score) AS total_score, 
        COUNT(user_mcq.id) AS num_taken 
        FROM user_mcq 
        INNER JOIN user ON (user.id = user_mcq.user_id) 
        WHERE user.level_id =3 
        AND user_mcq.is_complete =1 
        GROUP BY user_mcq.mcq_id 
      ) AS stat 
     ) AS stats 
SET mcq.avg_score = stats.avg_score 
WHERE mcq.mcq_id = stats.mcq_id; 
+0

doskonały, wielkie dzięki! :) – Adam

+0

fajnie .. to naprawdę oszczędzam mój czas .. – faruk

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